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NEET2019PhysicsCurrent ElectricityActual

The reading of an ideal voltmeter in the circuit shown is

Options

  1. A0.6 ~V
  2. B0 ~V
  3. C0.5 ~V
  4. D0.4 ~V

Correct answer

D. 0.4 ~V

Step-by-step solution

The given circuit diagram can be drawn as shown below The equivalent resistance of circuit is given by aligned & l R _ eq = l R _ AE + l R _ DF & = 1 (20+30) + 1 (30+20) & = 1 50 + 1 50 = 2 50 & R _ eq =25 & aligned As the resistance of two branches is same i.e. 50 . So, the current I ₁= I ₂ aligned I & = I ₁+ I ₂ 2 25 & =2 I ₁ I ₂= I ₁= 1 25 ~A aligned The voltage across AB V ₁= I ₁ R ₁= 1 25 20 and voltage across C D aligned V ₂= & I ₂ R ₂= 1 25 30 Voltmeter reading & = V ₂- V ₁ & = 30 25 - 20 25 & = 10 25 =0.4 ~

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