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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Current Electricity

NEET 2015 · Physics · Current Electricity

A potentiometer wire of length L and a resistance r are connected...

A potentiometer wire of length LL and a resistance rr are connected in series with a battery of e.m.f. E0{E}_{0} and a resistance r1{r}_{1} . An unknown e.m.f. EE is balanced at a length ll of the potentiometer wire. The e.m.f. EE will be given by:

Options

  1. AE0r(r+r1).lL\dfrac{{E}_{0}r}{\left(r + {r}_{1}\right)} . \dfrac{l}{L}
  2. BE0lL\dfrac{{E}_{0}l}{L}
  3. C\dfrac{L{E}_{0}r}{\left(r + {r}_{1}\right)l}
  4. DLE0rlr1\dfrac{L{E}_{0}r}{l{r}_{1}}

Correct answer

A. E0r(r+r1).lL\dfrac{{E}_{0}r}{\left(r + {r}_{1}\right)} . \dfrac{l}{L}

Step-by-step solution

K=K = potential gradient =(E0rr+r1)1L= \left(\dfrac{{E}_{0}r}{r + {r}_{1}}\right)\dfrac{1}{L}

So E=Kl=E0rl(r+r1)LE = Kl = \dfrac{{E}_{0}rl}{\left(r + {r}_{1}\right)L}
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