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NEET2015PhysicsCurrent ElectricityActual

A potentiometer wire of length L and a resistance r are connected in series with a battery of e.m.f. E 0 and a resistance r 1 . An unknown e.m.f. E is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by:

Options

  1. AE 0 r r + r 1 . l L
  2. BE 0 l L
  3. CL E 0 r r + r 1 l
  4. DL E 0 r l   r 1

Correct answer

A. E 0 r r + r 1 . l L

Step-by-step solution

K = potential gradient = E 0 r r + r 1 1 L So E = K l = E 0 r l r + r 1 L

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