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NEET 2014
Exam
NEET
Year
2014
Subject
Physics
Chapter
Current Electricity

NEET 2014 · Physics · Current Electricity

Two cities are 150km apart. Electric power is sent from one city to...

Two cities are 150km150km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per kmkm is 88 volts and the average resistance per kmkm is 0.5Ω.0.5Ω . The power loss in the wire is:

Options

  1. A19.2W19.2W
  2. B19.2kW19.2kW
  3. C19.2J19.2J
  4. D12.2kW12.2kW

Correct answer

B. 19.2kW19.2kW

Step-by-step solution

Distance between the two cities, 150km150km.

Voltage drop per kilometre is 8Vkm−18V{km}^{- 1}.

Resistance per kilometre 0.5Ωkm−10 . 5Ω{km}^{- 1}

Total voltage drop will be,
Vdrop=150km×8Vkm−1=1200V{V}_{drop} = 150km \times 8V{km}^{- 1} = 1200V

Total resistance of wire,
R=0.5Ωkm−1×150km=75ΩR = 0.5Ω{km}^{- 1} \times 150km = 75Ω

Therefore, the power loss will be, P=V2R=(150×8)20.5×150=19.2kWP = \dfrac{{V}^{2}}{R} = \dfrac{{\left(150 \times 8\right)}^{2}}{0.5 \times 150} = 19.2kW

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