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NEET 2013

Exam: NEET
Year: 2013
Subject: Physics
Chapter: Current Electricity

NEET 2013 · Physics · Current Electricity

The internal resistance of a 2.1 ~V cell which gives a current of...

The internal resistance of a

2.1 \mathrm{~V}

cell which gives a current of

0.2 \mathrm{~A}

through a resistance of

10 \Omega

is

Options

A $0.2 \Omega$
B $0.5 \Omega$
C $0.8 \Omega$
D $1.0 \Omega$

Correct answer

B. $0.5 \Omega$

Step-by-step solution

\begin{aligned} & I=\frac{E}{R+r} \\ & 0.2 \times(10+r)=2.1 \\ & 10+r=\frac{2.1}{2} \times 10 \\ & r=10.5-10=0.5 \Omega\end{aligned}

)$

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