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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Current Electricity

NEET 2012 · Physics · Current Electricity

The power dissipated in the circuit shown in the figure is 30 Watt....

The power dissipated in the circuit shown in the figure is 30 Watt. The value of RR is The power dissipated in the circuit shown in the figure is 30 Watt. The value of R is

Options

  1. A20Ω20 \Omega
  2. B15Ω15 \Omega
  3. C10Ω10 \Omega
  4. D30Ω30 \Omega

Correct answer

C. 10Ω10 \Omega

Step-by-step solution

Here, R1=R=R_1=R= ? R_2=5 \Omega, V=10  V\mathrm{~V}and P=30 W\quad P=30 \mathrm{~W} HenceP=V2R1+V2R2102R=30−1025100R=30−20R=10Ω\begin{aligned}P & =\frac{V^2}{R_1}+\frac{V^2}{R_2}\\ \frac{10^2}{R}& =30-\frac{10^2}{5}\\ \frac{100}{R}& =30-20 \\ R & =10 \Omega \end{aligned}
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