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NEET 2011
Exam
NEET
Year
2011
Subject
Physics
Chapter
Current Electricity

NEET 2011 · Physics · Current Electricity

If power dissipated in the 9 resistor in the circuit shown is 36 ~W...

If power dissipated in the 9Ω9 \Omega resistor in the circuit shown is 36 W36 \mathrm{~W}, the potential difference across the 2Ω2 \Omega resistor is If power dissipated in the 9 resistor in the circuit shown is 36 ~W , the potential difference across the 2 resistor is

Options

  1. A8 V8 \mathrm{~V}
  2. B10 V10 \mathrm{~V}
  3. C2 V2 \mathrm{~V}
  4. D4 V4 \mathrm{~V}

Correct answer

B. 10 V10 \mathrm{~V}

Step-by-step solution

Electric power, P=i2R∴P=i^2 R\therefore Current, i=PR\quad i=\sqrt{\frac{P}{R}} For resistance of 9Ω9 \Omega i_1=369=4=\sqrt{\frac{36}{9}}=\sqrt{4}=2  A\mathrm{~A}i2=i1×R6=2×96=3 Ai=i1+i2=2+3=5 AV2=IR2=5×2=10 V\begin{aligned}i_2 & =\frac{i_1 \times R}{6}=\frac{2 \times 9}{6}=3 \mathrm{~A}\\ i & =i_1+i_2=2+3=5 \mathrm{~A}\\ V_2 & =I R_2=5 \times2=10 \mathrm{~V} \end{aligned}$$
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