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NEET2014PhysicsCurrent ElectricityActual

A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of 2.0   V and a negligible internal resistance. The potentiometer wire itself is 4   m long. When the resistance, R , connected across the given cell, has values of. i infinity i i   9.5   Ω The 'balancing lengths, on the potentiome

Options

  1. A0.25 Ω
  2. B9.5   Ω
  3. C0.5 Ω
  4. D0.75 Ω

Correct answer

C. 0.5 Ω

Step-by-step solution

Here, we have to calculate the internal resistence of the unknown cell. So, we have to use the following formulae: Internal resistance of the unknown cell is r = l 1 l 2 - 1 R = 3 2.85 - 1 9.5 Ω = 0.5 Ω Hence the internal resistance will be 0.5 Ohm

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