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NEET2008PhysicsCurrent ElectricityActual

A current of 3 A flows through the 2 resistor shown in the circuit. The power dissipated in the 5 resistor is

Options

  1. A4 ~W
  2. B2 ~W
  3. C1 ~W
  4. D5 ~W

Correct answer

D. 5 ~W

Step-by-step solution

Key Idea : Voltage across 2 is same as voltage across arm containing 1 and 5 resistances. Voltage across 2 resistance, V=2 3=6 ~V So, voltage across lowest arm, V₁=6 ~V Current across 5 , I= 6 1+5 =1 ~A Thus, power across 5 , P=I^2 R=(1)^2 5=5 ~W

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