NEET2008PhysicsCurrent ElectricityActual
A wire of a certain material is stretched slowly by ten per cent. Its new resistance and specific resistance become respectively
Options
- A1.2 times, 1.1 times
- B1.21 times, same
- Cboth remain the same
- D1.1 times, 1.1 times
Correct answer
B. 1.21 times, same
Step-by-step solution
Key Idea : In stretching, specific resistance remains unchanged. After stretching, specific resistance ( ) will remain same. Original resistance of the wire, R= l A R l A or R l^2 V (as V=A l ) and R^ (l+10 % l)^2 V Therefore, R^ R = (l+ 10 100 l )^2 l^2 R^ R = ( 11 l 10 )^2 l^2 = 121 100 R^ =1.21 R