Power dissipated across the 8 resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 3 resistor is:

Step-by-step solution

1 and 3 are in series so, egin aligned & R_s=R₁+R₂ & R_s=3+1=4 aligned and R₂=8 net i= current in the circuit Current through R₁ is i₁= i R₂ R₁+R₂ = i 8 12 = 21 3 Current R₂ is i₂= 1 R₁ R₁+R₂ = i 4 12 = i 8 12 Power dissipated in 3 resistance is: P₁=l₁^2 3 Power dissipated in 8 resistance is: P₂=l₂^2 8 For (i) and (ii) aligned & P₁ P₂ = i₁^2 3 i₂^2 8 & P₁ P₂ aligned aligned & = ( 2 i 3 )^2 3 ( i 3 )^2 8 = 3 2 P₁ & = 3 2 P₂= 3 2 2 =3 ~W aligned aligned & P & =100 ~W , V=125 V & P & =V I & I & = P V = 100 125 A alig