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NEET2008PhysicsCurrent ElectricityActual

A galvanometer of resistance 50 is connected to a battery of 3 ~V along with a resistance of 2950 in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be

Options

  1. A4450
  2. B5050
  3. C5550
  4. D6050

Correct answer

A. 4450

Step-by-step solution

gathered 30 i₀= V R_g+2950 ; R_g=50 20 i₀= V R_g+R R=4450 gathered

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