NEET2023PhysicsDual Nature of MatterActual
The de Broglie wavelength associated with an electron, accelerated by a potential difference of 81 ~V is given by:
Options
- A1.36 ~nm
- B0.136 ~nm
- C13.6 ~nm
- D136 ~nm
Correct answer
B. 0.136 ~nm
Step-by-step solution
We know, for an electron De Broglie wavelength, = 12.27 v Å aligned & = 12.27 81 = 12.27 9 Å & =1.36 Å or 0.136 ~nm aligned