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The threshold frequency of a photoelectric metal is v₀ . If light of frequency 4 v₀ is incident on this metal, then the maximum kinetic energy of emitted electrons will be:

Options

  1. Ah v₀
  2. B2 h v₀
  3. C3 h v₀
  4. D4 h v ₀

Correct answer

C. 3 h v₀

Step-by-step solution

By using Einstein's photoelectric equation, we have, aligned & KE =h v- & KE =h v-h v₀ & = h (4 v₀ )-h v₀ & =3 h v₀ & where, h= Planck's constant, & v & v₀= frequencies, and & = work function. & aligned

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