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NEET2021PhysicsDual Nature of MatterActual

The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600   nm , when it delivers the power of 3 . 3 × 10 - 3   W will be : h = 6 . 6 × 10 - 34   J   s

Options

  1. A10 18
  2. B10 17
  3. C10 16
  4. D10 15

Correct answer

C. 10 16

Step-by-step solution

Energy of each photon, E = h c λ ⇒ E = 6 . 6 × 10 - 34 × 3 × 10 8 600 × 10 - 9 ⇒ E = 3 . 3 × 10 - 19   J Number of photons emitted per second, N = P E ⇒ N = 3 . 3 × 10 - 3 3 . 3 × 10 - 19 ⇒ N = 10 16

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