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An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10 – 2   nm , the potential difference is:

Options

  1. A10 2   V
  2. B10 3   V
  3. C10 4   V
  4. D10   V

Correct answer

C. 10 4   V

Step-by-step solution

λ = 1 . 227 × 10 − 2   nm = 0 . 1227 Å λ = 12 . 27 v Å 0 . 227 = 12 . 27 v Å v = 10 2 ⇒ v = 10 4 volt

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