NEET2018PhysicsDual Nature of MatterActual
An electron of mass m with an initial velocity V → = V 0   i ^     ( V 0 > 0 ) enters in an electric field E → = -E 0 i ^ ( E 0 > 0 and is a constant ) at t = 0 . If λ 0 is its de-Broglie wavelength initially, then its de-Broglie wavelength at time t is
Options
- Aλ 0 t
- Bλ 0 1 + e E 0 m V 0 t
- Cλ 0 1 + e E 0 m V 0 t
- Dλ 0
Correct answer
C. λ 0 1 + e E 0 m V 0 t
Step-by-step solution
V → = V 0 i ^ E → = - E 0 i ^ a → = F → m = q E → m = - e - E 0 i ^ m a → = e E 0 m i ^ V = u + a t V = V 0 + e E 0 m t ∵ De Broglie wavelength = λ = h m v and initially λ 0 = h m v 0 . =   h m V 0 + e E 0 t m = h m V 0 1 + e E 0 t m V 0 = λ 0 1 + e E 0 t m V 0