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NEET 2016

Exam: NEET
Year: 2016
Subject: Physics
Chapter: Dual Nature of Matter

NEET 2016 · Physics · Dual Nature of Matter

Photons with energy of 5eV are incident on a cathode, C in a...

Photons with energy of

5eV

are incident on a cathode,

C

in a photoelectric cell. The maximum energy of emitted photoelectrons is

2 eV.

When photons of energy

6 eV

are incident on

C

, no photoelectrons will reach the anode,

A

, if, the stopping potential of

A

relative to

C

is

Options

A $+ 3V$
B $+ 4V$
C $- 1V$
D $- 3V$

Correct answer

D. $- 3V$

Step-by-step solution

${E}_\max = E - ϕ$

$2eV = 5eV - ϕ ⇒ ϕ = 3eV$ .

Now, ${eV}_{0} = E - ϕ$

$= 6eV - 3eV = 3eV$ .

So, the stopping potential is $- 3V$ .

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