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Photons with energy of 5   eV are incident on a cathode, C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6   eV are incident on C , no photoelectrons will reach the anode, A , if, the stopping potential of A relative to C is

Options

  1. A+ 3 V
  2. B+ 4 V
  3. C- 1 V
  4. D- 3   V

Correct answer

D. - 3   V

Step-by-step solution

E max = E - ϕ 2   e V = 5   e V - ϕ ⇒ ϕ = 3   e V . Now, eV 0 = E - ϕ = 6   e V - 3   e V = 3   e V . So, the stopping potential is - 3   V .

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