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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Dual Nature of Matter

NEET 2013 · Physics · Dual Nature of Matter

A source of light is placed at a distance of 50 ~cm from a photo...

A source of light is placed at a distance of 50 cm50 \mathrm{~cm} from a photo cells and the stopping potential is found to be V0∗\mathrm{V}_{0^*}. If the distance between the light source and photo cells is made 25 cm25 \mathrm{~cm}, the new stopping potential will be:

Options

  1. AV0/2V_0 / 2
  2. BV0V_0
  3. C4V04 V_0
  4. D2V02 V_0

Correct answer

B. V0V_0

Step-by-step solution

Stopping potential is independent of distance hence new stopping potential will remain unchanged in required. Stopping potential =V0=V_0
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