A source S_1 is producing, 10^ 15 photons/s of wavelength 5000 Å . Another source S_2 is producing 1.02 × 10^ 15 photons per second of wavelength 5100 Å . Then, (power of .S_2) /(. power of S_1 ) is equal to

Correct answer: A. 1.00 Number of photons emitted per second array cc = P ( hc λ ) P= nhc λ P_2 P_1 = n_2 λ_1 n_1 λ_2 = 1.02 × 10^ 15 × 5000 10^ 15 × 5100 =1 array

NEET 2010

Exam: NEET
Year: 2010
Subject: Physics
Chapter: Dual Nature of Matter

NEET 2010 · Physics · Dual Nature of Matter

A source S_1 is producing, 10^ 15 photons/s of wavelength 5000 Å ....

A source

\mathrm{S}_1

is producing,

10^{15}

photons/s of wavelength

5000 Å

. Another source

S_2

is producing

1.02 \times 10^{15}

photons per second of wavelength

5100 Å

. Then, (power of \left.S_2\right) /\left(\right.

power of

S_1$ ) is equal to

Options

A1.00
B1.02
C1.04
D0.98

Correct answer

A. 1.00

Step-by-step solution

Number of photons emitted per second

\begin{array}{cc} \quad\mathrm{n}=\frac{\mathrm{P}}{\left(\frac{\mathrm{hc}}{\lambda}\right)}\\ \therefore \quad \mathrm{P}=\frac{\mathrm{nhc}}{\lambda}\\ \Rightarrow \frac{\mathrm{P}_2}{\mathrm{P}_1}=\frac{\mathrm{n}_2 \lambda_1}{\mathrm{n}_1 \lambda_2}=\frac{1.02 \times 10^{15} \times 5000}{10^{15} \times 5100}=1 \end{array}

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