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NEET2010PhysicsDual Nature of MatterActual

A source S ₁ is producing, 10¹⁵ photons/s of wavelength 5000 Å . Another source S₂ is producing 1.02 10¹⁵ photons per second of wavelength 5100 Å . Then, (power of .S₂ ) / ( . power of S₁ ) is equal to

Options

  1. A1.00
  2. B1.02
  3. C1.04
  4. D0.98

Correct answer

A. 1.00

Step-by-step solution

Number of photons emitted per second array cc n = P ( hc ) P = nhc P ₂ P ₁ = n ₂ ₁ n ₁ ₂ = 1.02 10¹⁵ 5000 10¹⁵ 5100 =1 array

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