NEET2008PhysicsDual Nature of MatterActual
The work function of a surface of a photosensitive material is 6.2 eV . The wavelength of the incident radiation for which the stopping potential is 5 ~V lies in the
Options
- Aultraviolet region
- Bvisible region
- Cinfrared region
- DX-ray region
Correct answer
A. ultraviolet region
Step-by-step solution
According to laws of photoelectric effect KE _ =E- where is work function and KE _ is maximum kinetic energy of photoelectron. array l h v=e V₀+ or h v=5 eV +6.2 eV =11.2 eV = ( 12400 11.2 ) Å 1000 Å array Hence, the radiation lies in ultraviolet region.