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NEET 2023
Exam
NEET
Year
2023
Subject
Physics
Chapter
Electromagnetic Waves

NEET 2023 · Physics · Electromagnetic Waves

To produce an instantaneous displacement current of 2 ~mA in the...

To produce an instantaneous displacement current of 2 mA2 \mathrm{~mA} in the space between the parallel plates of a capacitor of capacitance 4μF4 \mu \mathrm{F}, the rate of change of applied variable potential difference (dVdt)\left(\frac{d V}{d t}\right) must be

Options

  1. A200 V/s200 \mathrm{~V} / \mathrm{s}
  2. B400 V/s400 \mathrm{~V} / \mathrm{s}
  3. C800 V/s800 \mathrm{~V} / \mathrm{s}
  4. D500 V/s500 \mathrm{~V} / \mathrm{s}

Correct answer

D. 500 V/s500 \mathrm{~V} / \mathrm{s}

Step-by-step solution

 Displacement current id=cdVdt⇒2×10−3=4×10−6×dVdt⇒2×10−34×10−6=dVdt⇒dVdt=500V/s\begin{aligned} & \text{ Displacement current } i_d=c \frac{d V}{d t} \\ & \Rightarrow 2 \times 10^{-3}=4 \times 10^{-6} \times \frac{d V}{d t} \\ & \Rightarrow \frac{2 \times 10^{-3}}{4 \times 10^{-6}}=\frac{d V}{d t} \\ & \Rightarrow \frac{d V}{d t}=500 \mathrm{ V} / \mathrm{s}\end{aligned}
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