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NEET2023PhysicsElectromagnetic WavesActual

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2 . 0 × 10 10   Hz and amplitude 48   V   m - 1 . Then the amplitude of oscillating magnetic field is: (Speed of light in free space =   3 × 10 8   m   s - 1 )

Options

  1. A1 . 6 × 10 - 6   T
  2. B1 . 6 × 10 - 9   T
  3. C1 . 6 × 10 - 8   T
  4. D1 . 6 × 10 - 7   T

Correct answer

D. 1 . 6 × 10 - 7   T

Step-by-step solution

Frequency of oscillation = 2 × 10 10   Hz Given c = 3 × 10 8   m   s - 1 , Electric field amplitude E 0 = 48   V   m - 1 Using the formula,  c = E 0 B 0 The amplitude of the oscillating magnetic field B ⁡ 0 = E ⁡ 0 c = 4 8 3 × 1 0 8 = 1 . 6 × 1 0 - 7   T .

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