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NEET 2024
Exam
NEET
Year
2024
Subject
Physics
Chapter
Electrostatics

NEET 2024 · Physics · Electrostatics

A thin spherical shell is charged by some source. The potential...

A thin spherical shell is charged by some source. The potential difference between the two points CC and PP (in V ) shown in the figure is: (Take 14πε0=9×109\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 SI units) A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V ) shown

Options

  1. A1×1051 \times 10^5
  2. B0.5×1050.5 \times 10^5
  3. CZero
  4. D3×1053 \times 10^5

Correct answer

C. Zero

Step-by-step solution

For uniformly charged spherical shell, V=kqR( For r≤R)∴VC=VPVC−VP= Zero \begin{aligned} & V=\frac{k q}{R} \quad(\text{ For } r \leq R) \\ & \therefore \quad V_C=V_P \\ & \\ & V_C-V_P=\text{ Zero } \end{aligned}
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