Two hollow conducting spheres of radii R _ 1 and R _ 2 ( R _ 1 ≫ R _ 2 ) have equal charges. The potential would be:

Correct answer: A. more on smaller sphere Potential at the surface of the spheres will be given by, V = (kQ)/(R) . As charge on both the spheres is equal, therefore, smaller sphere will have higher potential.

NEET 2022

Exam: NEET
Year: 2022
Subject: Physics
Chapter: Electrostatics

NEET 2022 · Physics · Electrostatics

Two hollow conducting spheres of radii R _ 1 and R _ 2 ( R _ 1 ≫ R...

Two hollow conducting spheres of radii {R}_{1} and

{R}_{2} \left({R}_{1} ≫ {R}_{2}\right) have equal charges.

The potential would be:

Options

Amore on smaller sphere
Bequal on both the spheres
Cdependent on the material property of the sphere
Dmore on bigger sphere

Correct answer

A. more on smaller sphere

Step-by-step solution

Potential at the surface of the spheres will be given by,

V = \dfrac{kQ}{R}

. As charge on both the spheres is equal, therefore, smaller sphere will have higher potential.

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