The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1 . 6   Å apart is, m e ≃ 9 × 10 - 31   kg ,   e = 1 . 6 × 10 - 19   C (Take 1 4 π ε 0 = 9 × 10 9   N   m 2   C - 2 )

Step-by-step solution

Recall the formula of electrostatic force interns of charge on electron and septation between them, F = K e 2 r 2 , now use Newton's second law, m a = K e 2 r 2 ⇒ a = K e 2 m r 2 , so, the acceleration, a = 9 × 10 9 1 . 6 × 10 - 19 2 1 . 6 × 10 - 10 2 9 × 10 - 31 ⇒ a = 10 - 29 × 10 51 = 10 22   m   s - 2