A sphere encloses an electric dipole with charge ± 3 × 10^ -6 C ....

A sphere encloses an electric dipole with charge

\pm 3 \times 10^{-6} \mathrm{C}

. What is the total electric flux across the sphere? A sphere encloses an electric dipole with charge ± 3 × 10^ -6 C . What is the total electric flux across the sphere?

A sphere encloses an electric dipole with charge ± 3 × 10^ -6 C . What is the total electric flux across the sphere?

Options

A $-3 \times 10^{-6} \mathrm{~N}-\mathrm{m}^2 / \mathrm{C}$
Bzero
C $3 \times 10^6 \mathrm{~N}-\mathrm{m}^2 / \mathrm{C}$
D $6 \times 10^{-6} \mathrm{~N}-\mathrm{m}^2 / \mathrm{C}$

Correct answer

B. zero

Step-by-step solution

When a sphere encloses a charged dipole, A sphere encloses an electric dipole with charge ± 3 × 10^ -6 C . What is the total electric flux across the sphere?

Here,

q= \pm 3 \times 10^{-6} \mathrm{C}

Thus, according to Gauss's law, the net electric flux across the closed surface is equal to the net charge enclosed by it divided by

\varepsilon_0

, i.e.

\phi_{\mathrm{E}}=\frac{\mathrm{q}_{\mathrm{in}}}{\varepsilon_0}=\frac{+3 \times 10^{-6}-3 \times 10^{-6}}{\varepsilon_0}=0

Hence, electric flux across the sphere is zero.

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