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NEET 2019

Exam: NEET
Year: 2019
Subject: Physics
Chapter: Electrostatics

NEET 2019 · Physics · Electrostatics

Two point charges A and B, having charges + Q and - Q respectively,...

Two point charges A and B, having charges

+ Q

and

- Q

respectively, are placed at certain distance apart and force acting between them is

F

. If

25%

charge of

A

is transferred to

B

, then the force between the charges becomes

Options

A $F$ .
B $\dfrac{9F}{16}$ .
C $\dfrac{16F}{9}$ .
D $\dfrac{4F}{3}$ .

Correct answer

B. $\dfrac{9F}{16}$ .

Step-by-step solution

F = \dfrac{K{Q}^{2}}{{r}^{2}}

After transferring

25 %

of charge,

{q}_{1} = \dfrac{3Q}{4}

and

{q}_{2} = - \dfrac{3Q}{4}

{F}_{1} = \dfrac{9}{16}\dfrac{K{Q}^{2}}{{r}^{2}} = \dfrac{9}{16}F

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