Suppose the charge of a proton and an electron differ slightly. One of them is e , the other is (e + ) . If the net electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much

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Correct answer: C. 10 ^ - 37 C

The net electrostatic force and gravitational force will be equal since the net force on the system is zero. Thus,

{F}_{E} = {F}_{g}

\dfrac{1}{4\pi{ε}_{0}}\dfrac{\Delta{e}^{2}}{{d}^{2}} = \dfrac{G{m}^{2}}{{d}^{2}}

9 \times {10}^{9}\left(\Delta{e}^{2}\right) = 6.67 \times {10}^{- 11} \times 1.67 \times {10}^{- 27} \times 1.67 \times {10}^{- 27}

\Delta{e}^{2} = \dfrac{6.67 \times 1.67 \times 1.67}{9} \times {10}^{- 74}

\Deltae \approx {10}^{- 37}

Suppose the charge of a proton and an electron differ slightly. One...

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