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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Electrostatics

NEET 2012 · Physics · Electrostatics

An electric dipole of moment p is placed in an electric field of...

An electric dipole of moment pp is placed in an electric field of intensity EE. The dipole acquires a position such that the axis of the dipole makes an angle θ\theta with the direction of the field. Assuming that the potential energy of the dipole to be zero when θ=90∘\theta=90^{\circ}, the torque and the potential energy of the dipole will respectively beAn electric dipole of moment p is placed in an electric field of intensity E . The dipole acquires a position such that

Options

  1. ApEsin⁡θ,−pEcos⁡θp E \sin \theta,-p E \cos \theta
  2. BpEsin⁡θ,−2pEcos⁡θp E \sin \theta,-2 p E \cos \theta
  3. CpEsin⁡θ,2pEcos⁡θp E \sin \theta, 2 p E \cos \theta
  4. DpEcos⁡θ,−pEsin⁡θp E \cos \theta,-p E \sin \theta

Correct answer

A. pEsin⁡θ,−pEcos⁡θp E \sin \theta,-p E \cos \theta

Step-by-step solution

Here, Torque τ=pEsin⁡θ\tau=p E \sin \theta An electric dipole of moment p is placed in an electric field of intensity E . The dipole acquires a position such that
Potential energy of the dipole U=−∫τdθ=−∫π/20pEsin⁡θdθ=pE[cos⁡θ−0]=−pEcos⁡θ\begin{aligned} U & =-\int \tau d \theta \\ & =-\int_{\pi / 2}^0 p E \sin \theta d \theta=p E[\cos \theta-0] \\ & =-p E \cos \theta \end{aligned}
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