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NEET2011PhysicsElectrostaticsActual

The electric potential V at any point (x, y, z) , all in metres in space is given by V=4 x^2 volt. The electric field at the point (1,0,2) in volt/metre is

Options

  1. A8 along positive X -axis
  2. B16 along negative X -axis
  3. C16 along positive X -axis
  4. D8 along negative X -axis

Correct answer

D. 8 along negative X -axis

Step-by-step solution

We know that E =- [ i V x + j V y + k V z ] So aligned & E =- i V x =- i x (4 x^2 ) &=-8 x i Vm ⁻¹ & E _ (1,0,2) =-8 i Vm ⁻¹ aligned

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