As per the diagram a point charge +q is placed at the origin O . Work done in taking another point charge -Q from the point A [coordinate (0, a) ] to another point B [coordinates (a, 0) ] along the straight path AB is:

Correct answer: A. zero Work done is equal to zero because the potential of A and B are the same =(1)/(4 π _0) (q)/(a) No work done if a particle does not change its potential energy. i.e. initial potential energy = final potential energy.

NEET 2005

Exam: NEET
Year: 2005
Subject: Physics
Chapter: Electrostatics

NEET 2005 · Physics · Electrostatics

As per the diagram a point charge +q is placed at the origin O ....

As per the diagram a point charge

+q

is placed at the origin

\mathrm{O}

. Work done in taking another point charge

-\mathrm{Q}

from the point

\mathrm{A}

[coordinate

(0, a)

] to another point

\mathrm{B}

[coordinates

(a, 0)

] along the straight path

\mathrm{AB}

is:

As per the diagram a point charge +q is placed at the origin O . Work done in taking another point charge -Q from the

Options

Azero
B $\left(\frac{q Q}{4 \pi \varepsilon_0} \frac{1}{a^2}\right) \cdot \sqrt{2} a$
C $\left(\frac{-q Q}{4 \pi \varepsilon_0} \frac{1}{a^2}\right) \cdot \sqrt{2} a$
D $\left(\frac{q Q}{4 \pi \varepsilon_0} \frac{1}{a^2}\right) \cdot \frac{a}{\sqrt{2}}$

Correct answer

A. zero

Step-by-step solution

Work done is equal to zero because the potential of A and B are the same

=\frac{1}{4 \pi \epsilon_0} \frac{q}{a}

No work done if a particle does not change its potential energy. i.e. initial potential energy = final potential energy.

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