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NEET 2004
Exam
NEET
Year
2004
Subject
Physics
Chapter
Electrostatics

NEET 2004 · Physics · Electrostatics

A bullet of mass 2 ~g is having of 2 μ C . Through what potential...

A bullet of mass 2 g2 \mathrm{~g} is having of 2μC2 \mu \mathrm{C}. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of of 10 m/s10 \mathrm{~m} / \mathrm{s} ?

Options

  1. A5kV5 \mathrm{kV}
  2. B50kV50 \mathrm{kV}
  3. C5 V5 \mathrm{~V}
  4. D50 V50 \mathrm{~V}

Correct answer

B. 50kV50 \mathrm{kV}

Step-by-step solution

Here we apply 12mv2=qV\frac{1}{2} m v^2=q V \RightarrowV=12×2×10−3×10×102×10−6=50kV\begin{gathered} \RightarrowV=\frac{1}{2} \times \frac{2 \times 10^{-3} \times 10 \times 10}{2 \times 10^{-6}}\\ =50 \mathrm{kV} \end{gathered}
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