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NEET 2003
Exam
NEET
Year
2003
Subject
Physics
Chapter
Electrostatics

NEET 2003 · Physics · Electrostatics

An electron is moving around the nucleus of a hydrogen atom in a...

An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius rr. The coulomb force F⃗\vec{F} between the two is: (\left(\right. where K=14πε0)\left.K=\frac{1}{4 \pi \varepsilon_0}\right)

Options

  1. AKe2r2r^K \frac{e^2}{r^2} \hat{r}
  2. B−Ke2r3r^-K \frac{e^2}{r^3} \hat{r}
  3. CKe2r3r^K \frac{e^2}{r^3} \hat{r}
  4. D−Ke2r3r^-K \frac{e^2}{r^3} \hat{r}

Correct answer

D. −Ke2r3r^-K \frac{e^2}{r^3} \hat{r}

Step-by-step solution

The charge on hydrogen nuclear q1q_1=+ve∴ Coulomb’s force F=Kq1q2r2=K(+e)(−e)r2=−ke2r2r^\begin{aligned} & =+v e \\ & \therefore \text{ Coulomb's force } F=K \frac{q_1 q_2}{r^2} \\ & =K \frac{(+e)(-e)}{r^2}=-\frac{k e^2}{r^2} \hat{r} \end{aligned}$$
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