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NEET 2018
Exam
NEET
Year
2018
Subject
Physics
Chapter
Experimental Physics

NEET 2018 · Physics · Experimental Physics

A student measured the diameter of a small steel ball using a screw...

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001cm0 . 001cm. The main scale reading is 5mm5mm and 25th{25}^{th} division of circular scale coincides with reference line. If screw gauge has a zero error of −0.004cm- 0 . 004cm, the correct diameter of the ball is

Options

  1. A0.053cm0 . 053cm
  2. B0.525cm0 . 525cm
  3. C0.521cm0 . 521cm
  4. D0.529cm0 . 529cm

Correct answer

D. 0.529cm0 . 529cm

Step-by-step solution

Diameter of the steel ball = main scale reading + (circular scale reading × Least count) - zero error

=MSR+(CSR×L.C)−= MSR + ( CSR \times L . C ) - zero error

=0.5cm+25×0.001−(−0.004)= 0.5cm + 25 \times 0.001 - ( - 0.004 )

=0.5+0.025+0.004= 0.5 + 0.025 + 0.004

=0.529cm= 0.529cm

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