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NEET2018PhysicsExperimental PhysicsActual

A student measured the diameter of a small steel ball using a screw gauge of least count 0 . 001   cm . The main scale reading is 5   mm and 25 t h division of circular scale coincides with reference line. If screw gauge has a zero error of - 0 . 004   cm , the correct diameter of the ball is

Options

  1. A0 . 053   cm
  2. B0 . 525   cm
  3. C0 . 521   cm
  4. D0 . 529   cm

Correct answer

D. 0 . 529   cm

Step-by-step solution

Diameter of the steel ball = main scale reading + (circular scale reading × Least count) - zero error = MSR + ( CSR × L . C ) − zero error = 0.5 cm + 25 × 0.001 − ( − 0.004 ) = 0.5 + 0.025 + 0.004 = 0.529 cm

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