NEET2021PhysicsGravitationActual
The escape velocity from the Earth's surface is v . The escape velocity from the surface of another planet having a radius four times that of Earth and the same mass density is:
Options
- Av
- B2 v
- C3 v
- D4 v
Correct answer
D. 4 v
Step-by-step solution
Given, Escape velocity from earth's surface = v v = v e a r t h   = 2 g R = 2 G M 4 3 π R 3 4 3 π R 2 = 2 G M V 4 3 π R 2 = 8 G ρ π R 2 3 g = Gravitation acceleration on earth surface R = Radius of earth G = Universal gravitational constant Escape velocity of another planet = ? ∵ R p = 4 R & ρ p l a n e t   = ρ e a r t h So we can write, v e ∝ R 2 ∝ R v e e a r t h   v e p l a n e t   = R e a r t h   R p l a n e t   = R 4 R =