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NEET2021PhysicsGravitationActual

The escape velocity from the Earth's surface is v . The escape velocity from the surface of another planet having a radius four times that of Earth and the same mass density is:

Options

  1. Av
  2. B2 v
  3. C3 v
  4. D4 v

Correct answer

D. 4 v

Step-by-step solution

Given, Escape velocity from earth's surface = v v = v e a r t h   = 2 g R = 2 G M 4 3 π R 3 4 3 π R 2 = 2 G M V 4 3 π R 2 = 8 G ρ π R 2 3 g = Gravitation acceleration on earth surface R = Radius of earth G = Universal gravitational constant Escape velocity of another planet = ? ∵ R p = 4 R & ρ p l a n e t   = ρ e a r t h So we can write, v e ∝ R 2 ∝ R v e e a r t h   v e p l a n e t   = R e a r t h   R p l a n e t   = R 4 R =

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