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NEET2019PhysicsGravitationActual

Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass m , when taken to a height h from the surface of earth (of radius R ) is given by,

Options

  1. A- G M m R+h
  2. BG M m h R(R+h)
  3. Cmgh
  4. DG M m R+h

Correct answer

B. G M m h R(R+h)

Step-by-step solution

The gravitational potential energy of an object placed at earth's surface is U ₁=- GMm R where, G= gravitational constant, M= Mass of earth, m= mass of object and R = radius of the earth The negative sign in the above relation indicates that it is the work done in bringing the object from infinity to a distance R . The gravitational potential energy of object at a height habove the surface of earth is U ₂=- GMm ( R + h ) So, the change in potential energy is aligned U & = U ₂- U ₁=- GMm R + h - (- GMm R ) & =- GMm

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