A remote-sensing satellite of earth revolves in a circular orbit at a height of $0.25 \times {10}^{6}$ m above the surface of earth. If earth's radius is $6.38 \times {10}^{6}m$ and $g = 9.8m{s}^{- 2}$ , then the orbital speed of the satellite is:
Mass of earth undefined

Question

A remote-sensing satellite of earth revolves in a circular orbit at a height of

0.25 \times {10}^{6}

m above the surface of earth. If earth's radius is

6.38 \times {10}^{6}m

and

g = 9.8m{s}^{- 2}

, then the orbital speed of the satellite is:
Mass of earth undefined

Quantrex Academy · Accepted Answer

Correct answer: D. 7.76km s ^ - 1

V _ 0 = (GM)/(r) = GM R ^ 2 . R ^ 2 r = 9.8 × 6.38 × 6.38 6.63 × 10 ^ 6 = 60 × 10 ^ 6 m/sec = 7.76 km/sec

A remote-sensing satellite of earth revolves in a circular orbit at...