Dependence of intensity of gravitational field (E) of earth with...

Here we have to find the graph between (E) and (r) in the given situation.

We know that,

$E = - \dfrac{GM}{{R}^{3}} \times \overset{\to}{r}\left(ifr < R\right)$ So, E is directly proportional to r and there is a negative sign. Hence graph will be straight line in 2nd quadrant starting from origin like the case of uniform motion in negative direction.
$E = - \dfrac{GM}{{r}^{3}} \times \overset{\to}{r}\left(ifr \ge R\right)$So, E is inversly proportional to${r}^{2}$ and there is a negative sign. Hence graph will be like as shown in this figure.