A body weighs 72N on the surface of the earth. What is the...

A body weighs

72N

on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

Options

A $32N$
B $30N$
C $24N$
D $48N$

Correct answer

A. $32N$

Step-by-step solution

${W}_{s} = m{g}_{s} = 72N$

${W}_{h} = m{g}_{h} = \dfrac{m{g}_{s}}{{\left(1 + \dfrac{h}{R}\right)}^{2}} = \dfrac{72N}{{\left(1 + \dfrac{R / 2}{R}\right)}^{2}} = \dfrac{72}{9 / 4}$

${W}_{h} = 32N$

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