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NEET2016PhysicsGravitationActual

A satellite of mass m is orbiting the earth (of radius R ) at a height h from its surface. The total energy of the satellite in terms of g o , the value of acceleration due to gravity at the earth's surface, is

Options

  1. Am g 0 R 2 2 R + h
  2. B- m g 0 R 2 2 R + h
  3. C2 m g 0 R 2 R + h
  4. D- 2 m g 0 R 2 R + h

Correct answer

B. - m g 0 R 2 2 R + h

Step-by-step solution

The total energy of a satellite in the orbit is E = - G M m 2 r r = R + h g 0 = G M R 2 ⇒ E = - m g 0 R 2 2 R + h

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