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NEET 2005
Exam
NEET
Year
2005
Subject
Physics
Chapter
Gravitation

NEET 2005 · Physics · Gravitation

For a satellite in an orbit around the earth, the ratio of kinetic...

For a satellite in an orbit around the earth, the ratio of kinetic energy to potential energy is:

Options

  1. A12\frac{1}{2}
  2. B12\frac{1}{\sqrt{2}}
  3. C2
  4. D2\sqrt{2}

Correct answer

A. 12\frac{1}{2}

Step-by-step solution

−GMmR2+mω2R=0-\frac{\mathrm{GMm}}{R^2}+m \omega^2 R=0∴GMmR2=mω2R K.E. =12Iω2=12mR2ω2=GMm2R\begin{aligned} \therefore \quad\frac{\mathrm{GMm}}{R^2}& =m \omega^2 R \\ \text{ K.E. }=\frac{1}{2}I \omega^2 & =\frac{1}{2}m R² \omega^2 \\ & =\frac{\mathrm{GMm}}{2 R} \end{aligned}P.E.=−GMmR\thereforeK.E=∣P⋅E∣2∴K⋅EP⋅E=12\begin{aligned}& P . E .=-\frac{\mathrm{GMm}}{R} \thereforeK . E=\frac{|P \cdot E|}{2}\\ & \therefore \quad \frac{K \cdot E}{P \cdot E}=\frac{1}{2} \end{aligned}$$
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