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NEET 2002
Exam
NEET
Year
2002
Subject
Physics
Chapter
Gravitation

NEET 2002 · Physics · Gravitation

A body of mass m is placed on Earth's surface which is a taken from...

A body of mass mm is placed on Earth's surface which is a taken from Earth's surface to a height of h=3Rh=3 R, then the change in the gravitational potential energy is:

Options

  1. AmgR4\frac{m g R}{4}
  2. B23mgR\frac{2}{3} m g R
  3. C34mgR\frac{3}{4} m g R
  4. DmgR2\frac{m g R}{2}

Correct answer

C. 34mgR\frac{3}{4} m g R

Step-by-step solution

∴ change in  GPE = final  energy − initial energy =−GMm4R+GMmR=−GMm4R[1−14]=34GMm4R=34GMR2mR=34gmR\begin{aligned} & \therefore \text{ change\text{ in } GPE }=\text{ final } \\ & \text{ energy }- \text{ initial energy } \\ & =-\frac{G M m}{4 R}+\frac{\mathrm{GMm}}{R} \\ & =-\frac{G M m}{4 R}\left[1-\frac{1}{4}\right]=\frac{3}{4} \frac{G M m}{4 R} \\ & =\frac{3}{4} \frac{G M}{R^2} m R=\frac{3}{4} g m R \end{aligned}
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