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NEET 2016
Exam
NEET
Year
2016
Subject
Physics
Chapter
Kinetic Theory of Gases

NEET 2016 · Physics · Kinetic Theory of Gases

The molecules of a given mass of gas have RMS velocity of 200 m s ^...

The molecules of a given mass of gas have RMS velocity of 200200 ms−1m{s}^{- 1} at 27oC{27}^{o}C and 1.0×105Nm−21.0 \times {10}^{5}N{m}^{- 2} pressure. When the temperature and pressure of the gas are respectively, 127oC{127}^{o}C and 0.05×105Nm−20.05 \times {10}^{5}N{m}^{- 2}, the r.m.s. velocity of its molecules in ms−1m{s}^{- 1} is:

Options

  1. A1002100\sqrt{2}
  2. B4003\dfrac{400}{\sqrt{3}}
  3. C10023\dfrac{100\sqrt{2}}{3}
  4. D1003\dfrac{100}{3}

Correct answer

B. 4003\dfrac{400}{\sqrt{3}}

Step-by-step solution

RMS speed of molecules is VRMS=3RTM{V}_{RMS} = \sqrt{\dfrac{3RT}{M}}, where RR is universal gas constant, TT is absolute temperature and MM is molar mass of gas.

So it depends only on temperature, Vrms∝T{V}_{rms} ∝ \sqrt{T}

⇒V1V2=T1T2⇒200V2=300400⇒ \dfrac{{V}_{1}}{{V}_{2}} = \sqrt{\dfrac{{T}_{1}}{{T}_{2}}} ⇒ \dfrac{200}{{V}_{2}} = \sqrt{\dfrac{300}{400}}

⇒200V2=32⇒V2=4003msec−1⇒ \dfrac{200}{{V}_{2}} = \dfrac{\sqrt{3}}{2} ⇒ {V}_{2} = \dfrac{400}{\sqrt{3}}m{sec}^{- 1}

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