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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Kinetic Theory of Gases

NEET 2013 · Physics · Kinetic Theory of Gases

In a vessel, the gas is at pressure P , if the mass of all the...

In a vessel, the gas is at pressure PP, if the mass of all the molecules is halved of their speed is double, then the resultant pressure will be :

Options

  1. A2P2 P
  2. BPP
  3. CP/2P / 2
  4. D4P4 P

Correct answer

A. 2P2 P

Step-by-step solution

The equation of pressure is P=13m Nv2\frac{1}{3} \frac{m \mathrm{~N}}{v^2}v_{r m s}^2 where m=m= mass of each molecules N= number of  molecules  V= volume of the gas \begin{aligned}& N=\text{ number\text{ of }\text{ molecules } }\\ & V=\text{ volume of the gas } \end{aligned}According to the question: mass of all molecules is halved an velocity is double then P′=13(m2)×NV×((2 Vras)2=23m N V Vras2=2P\begin{aligned} \mathrm{P}^{\prime}=\frac{1}{3}\left(\frac{m}{2}\right) \times \frac{\mathrm{N}}{\mathrm{V}} \times(& \left(2 \mathrm{~V}_{\mathrm{ras}}\right)^2 \\ & =\frac{2}{3} \frac{m \mathrm{~N}}{\mathrm{~V}} \mathrm{~V}_{\mathrm{ras}}^2 \\ & =2 \mathrm{P} \end{aligned}compare with eq (i) P′=2PP′=2P\begin{aligned}& \mathrm{P}^{\prime}=2 \mathrm{P}\\ & \mathrm{P}^{\prime}=2 \mathrm{P} \end{aligned}
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