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NEET 2025
Exam
NEET
Year
2025
Subject
Physics
Chapter
Kinetic Theory of Gases

NEET 2025 · Physics · Kinetic Theory of Gases

An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen....

An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature 27∘C27^{\circ} \mathrm{C}. The mass of the oxygen withdrawn from the cylinder is nearly equal to : [Given, R=10012 J mol−1 K−1R=\frac{100}{12} \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, and molecular mass of O2=32,1 atmO_2=32,1 \mathrm{~atm} pressure =1.01×105 N/m]\left.=1.01 \times 10^5 \mathrm{~N} / \mathrm{m}\right]

Options

  1. A0.125 kg0.125 \mathrm{~kg}
  2. B0.144 kg0.144 \mathrm{~kg}
  3. C0.116 kg0.116 \mathrm{~kg}
  4. D0.156 kg0.156 \mathrm{~kg}

Correct answer

C. 0.116 kg0.116 \mathrm{~kg}

Step-by-step solution

nf=PfVRT[Pabs=12atm]=12×1.01×105×30×10−3(10012)×300=14.544∴ moles removed =18.2−14.544=3.656∴ mass removed =3.656×321000kg=0.116kg\begin{aligned} & \mathrm{n}_{\mathrm{f}}=\frac{\mathrm{P}_{\mathrm{f}} \mathrm{V}}{\mathrm{RT}} \quad\left[\mathrm{P}_{\mathrm{abs}}=12 \mathrm{ atm}\right] \\ & =\frac{12 \times 1.01 \times 10^5 \times 30 \times 10^{-3}}{\left(\frac{100}{12}\right) \times 300} \\ & =14.544 \\ & \therefore \text{ moles removed }=18.2-14.544=3.656 \\ & \therefore \text{ mass removed }=3.656 \times \frac{32}{1000} \mathrm{ kg}=0.116 \mathrm{ kg}\end{aligned}
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