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NEET 2018
Exam
NEET
Year
2018
Subject
Physics
Chapter
Kinetic Theory of Gases

NEET 2018 · Physics · Kinetic Theory of Gases

At what temperature will the rms speed of oxygen molecules becomes...

At what temperature will the rms speed of oxygen molecules becomes just sufficient for escaping from the Earth's atmosphere? (Given Mass of oxygen molecules m=2.76×10−26kgm = 2.76 \times {10}^{- 26}kg, Boltzmann's constant kB=1.38×10−23JK−1{k}_{B} = 1.38 \times {10}^{- 23}J{K}^{- 1})

Options

  1. A5.016×104K5.016 \times {10}^{4}K
  2. B8.360×104K8.360 \times {10}^{4}K
  3. C2.508×104K2.508 \times {10}^{4}K
  4. D1.254×104K1.254 \times {10}^{4}K

Correct answer

B. 8.360×104K8.360 \times {10}^{4}K

Step-by-step solution

Ve=Vrms{V}_{e} = {V}_{rms}

11.2×103=3kTm⇒T=(11.2×103)2m3k11.2 \times {10}^{3} = \sqrt{\dfrac{3kT}{m}} ⇒ T = \dfrac{{\left(11.2 \times {10}^{3}\right)}^{2}m}{3k}

Putting value of mm and kk

T=8.360×104KT = 8.360 \times {10}^{4}K
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