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NEET 2004
Exam
NEET
Year
2004
Subject
Physics
Chapter
Laws of Motion

NEET 2004 · Physics · Laws of Motion

The coefficient of static friction μ_8 , between block A of mass 2...

The coefficient of static friction μ8\mu_8, between block AA of mass 2 kg2 \mathrm{~kg} and the table as shown in the figure is 0.2 . What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless (g(g =10 m/s2)\left.=10 \mathrm{~m} / \mathrm{s}^2\right) The coefficient of static friction μ_8 , between block A of mass 2 ~kg and the table as shown in the figure is 0.2 .

Options

  1. A2.0 kg2.0 \mathrm{~kg}
  2. B4.0 kg4.0 \mathrm{~kg}
  3. C0.2 kg0.2 \mathrm{~kg}
  4. D0.4 kg0.4 \mathrm{~kg}

Correct answer

D. 0.4 kg0.4 \mathrm{~kg}

Step-by-step solution

According to the question T=mBT=m_{\mathrm{B}} q=\mu \left(m_{\mathrm{A}} q\right)<imgsrc="/api/proxy−image?url=https<img src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fneet%252FrSOQO-SUIt47MJNElUv2iUCRWhql5i2GjOpn1EklMJU.original.fullsize.png%3Falt%3Dmedia&clean=1&v=wm2" data-qx-orig-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fneet%2FrSOQO-SUIt47MJNElUv2iUCRWhql5i2GjOpn1EklMJU.original.fullsize.png?alt=media" data-qx-storage-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fneet%2FrSOQO-SUIt47MJNElUv2iUCRWhql5i2GjOpn1EklMJU.original.fullsize.png?alt=media"> \\ ⇒mB=μmA=0.02×2=0.4kg\begin{aligned} \Rightarrow \quad m_{\mathrm{B}} & =\mu m_{\mathrm{A}}=0.02 \times2 \\ & =0.4 \mathrm{ kg} \end{aligned}
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