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NEET 2004
Exam
NEET
Year
2004
Subject
Physics
Chapter
Laws of Motion

NEET 2004 · Physics · Laws of Motion

Two springs of spring constant k_1 and k_2 are joined in series....

Two springs of spring constant k1k_1 and k2k_2 are joined in series. The effective spring constant of the combination is given by:

Options

  1. Ak1k2\sqrt{k_1 k_2}
  2. B(k1+k2)/2\left(k_1+k_2\right) / 2
  3. Ck1+k2k_1+k_2
  4. Dk1k2/(k1+k2)k_1 k_2 /\left(k_1+k_2\right)

Correct answer

D. k1k2/(k1+k2)k_1 k_2 /\left(k_1+k_2\right)

Step-by-step solution

When the spring joined in series the total extension of spring is: \begin{aligned} & \Rightarrow y=y_1+y_2=\frac{-F}{k_1}-\frac{F}{k_2} \\ & \Rightarrow \quad y=-\mathrm{F}\left[\frac{1}{k_1}+\frac{1}{k_2}\right] \\ & \therefore \text{ Spring constant } k=\frac{k_1 k_2}{k_1+k_2} \end{aligned}
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