A block mass m is placed on a smooth wedge of inclination θ . The...

A block mass

m

is placed on a smooth wedge of inclination

\theta

. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (

g

is acceleration due to gravity) will be: A block mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the

A block mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the

Options

A $m g \cos \theta$
B $m g \sin \theta$
C $m g$
D $\mathrm{mg} / \cos \theta$

Correct answer

D. $\mathrm{mg} / \cos \theta$

Step-by-step solution

Here

N \cos \theta=m g

\Rightarrow N=\frac{m g}{\cos \theta}

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