An infinitely long straight conductor carries a current of 5 A as shown. An electron is moving with a speed of 10 5   m   s - 1 parallel to the conductor. The perpendicular distance between the electron and the conductor is 20   cm at an instant. Calculate the magnitude of the force experienced by the electron at that instant.

Step-by-step solution

Magnetic Field due to a current carrying wire at 20   cm in terms of current I is given by, B = μ 0 I 2 π d B = 2 × 10 - 7 × 5 20 × 10 - 2 B = 0 . 5 × 10 - 5   T Now, Force on charge particle = qvB F m = e V B F m = 1 . 6 × 10 - 19 × 10 5 × 0 . 5 × 10 - 5 = 8 × 10 - 20   N